dvsadvaith dvsadvaith
  • 11-06-2020
  • Mathematics
contestada

4^x-4^x-1=24,then find (2x)^x

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tramserran
tramserran tramserran
  • 11-06-2020

Answer:  5²⁻⁵

Step-by-step explanation:

[tex]4^x-4^{x-1}=24\\\\\\3(4^{x-1})=24\\\\\\4^{x-1}=8\\\\\\2^{2(x-1)}=2^3\\\\\\2(x-1)=3\\\\\\x-1=\dfrac{3}{2}\\\\\\x=\dfrac{5}{2}\quad \rightarrow x=2.5[/tex]

[tex](2x)^x\quad =(2\cdot 2.5)^{2.5}\quad =\large\boxed{5^{2.5}}[/tex]

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