Answer:
x = 2
Step-by-step explanation:
Given
[tex]\sqrt{x^3+41}[/tex]
Consider the perfect square closest to 41, that is 49
We require to add 8 to 41 to obtain 49
Now 8 = 2³
Thus
[tex]\sqrt{2^3+41}[/tex] = [tex]\sqrt{8+41}[/tex] = [tex]\sqrt{49}[/tex] = 7 ← a rational number
Thus x = 2 is the required value for x
