Answer:
V = 0.01(R₁ + R₂)
Explanation:
From Ohm's law, the voltage V across a resistor with resistance R and a current I passing through it is given by
V = IR
If we have two resistances, R₁ and R₂ in series, the total resistance R is the sum of their resistances.
So, R = R₁ + R₂
Now, if the current in the circuit is 0.01 A, the voltage V is
V = IR
V = 0.01R
Substituting R = R₁ + R₂ into the equation for V, we have
V = 0.01(R₁ + R₂)
So, the voltage in two series resistors with current 0.01 A is
V = 0.01(R₁ + R₂)
