Answer:
[tex]\frac{16}{9}[/tex].
Step-by-step explanation:
[tex](2^8*3^{-5}*6^0)^{-2}*(\frac{3^{-2}}{2^3})^4*2^{28}\\ (2^8*\frac{1}{3^5}*1)^{-2}*\frac{\frac{1}{3^8} }{\frac{2^{12}}{1} }*2^{28} \\ (\frac{2^8}{3^5})^{-2} * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{1}{\frac{2^8*2}{3^{5*2}} } * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{\frac{1}{1} }{\frac{2^{16}}{3^{10}} } * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{3^{10}}{2^{16}} * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{2^{28}}{2^{24}*3^2} = \frac{2^4}{3^2}=\frac{16}{9}[/tex]
