peachypants200 peachypants200
  • 14-07-2020
  • Mathematics
contestada

A line passes through the points (15,−13) and (16,−11). what would the equation be

Respuesta :

Аноним Аноним
  • 14-07-2020

Answer:

y= 2x - 43

Step-by-step explanation:

I'm going to assume that you want this in y=mx+b form.

Let's look for (m), the slope first.

The slope formula is [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]y_2[/tex] = -11

[tex]y_1[/tex] = -13

[tex]x_2[/tex] = 16

[tex]x_1[/tex] = 15

[tex]\frac{-11-(-13)}{16-15}[/tex] = [tex]\frac{-11+13}{1}[/tex] = [tex]\frac{2}{1}[/tex] = 2

The slope is 2.  --> y=2x+b

Let's substitute points in to fit b.

y= -11

x = 16

-11=2(16)+b

-11=32+b

b=-43

y= 2x - 43

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