ThePhantomWolf
ThePhantomWolf ThePhantomWolf
  • 14-07-2020
  • Mathematics
contestada

Solve each equation. [tex]32^{x-1}[/tex] = [tex]16^{x/4}[/tex] (The / is a division symbol not a fraction symbol) A.) 24 B.) 21 C.) -21 D.) 11

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 15-07-2020

Answer:

  x = 5/4

Step-by-step explanation:

32^(x-1) = 16^(x/4)

(2^5)^(x-1) = (2^4)^(x/4) . . . . . express as powers of 2

2^(5x -5) = 2^x . . . . . . simplify

5x -5 = x . . . . . . equate exponents

4x = 5 . . . . . . . . add 5-x

x = 5/4

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Applicable rules of exponents are ...

  (a^b)^c = a^(bc)

_____

Since this solution does not match any offered answer choice, we suggest you ask your teacher to show you how to work this problem.

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