beautifulnoob325
beautifulnoob325 beautifulnoob325
  • 02-08-2020
  • Mathematics
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Help!! I WILL GIVE BRAINLIEST I NEED HELPPPPPPPPPPPPPPPPPPP PLEASE PLEASE PLEASE PLEASEEEEEEEEEEEEE IM DEADD I REALLY NEED HELP ASAP ITS URGENT

Help I WILL GIVE BRAINLIEST I NEED HELPPPPPPPPPPPPPPPPPPP PLEASE PLEASE PLEASE PLEASEEEEEEEEEEEEE IM DEADD I REALLY NEED HELP ASAP ITS URGENT class=

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swan85 swan85
  • 02-08-2020

Answer:

arc axb=4.938

Step-by-step explanation:

to find the  measure of arc AXB find angle P first

length of the arc=rФ

in triangle APQ sin angle APQ= opp/hyp=AQ(radius)/PQ=5/√5+√21

in traingle PQB sin angle BPQ= opp/hyp.=5/√5+√21

angle P"

2arcsin 5/√5+√21= 94.324 degrees=(π*94.324)/180=1.64626 rad.

arc AXB=Фr (Ф=94.324 , r=3)

arc axb=4.938

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