hihihi11138 hihihi11138
  • 11-08-2020
  • Mathematics
contestada

Hi i wanna know if this is correct (x^2-4x)^2+7x^2-28x+12=0 I got: x^4-x^2-28x=-12 please help me

Respuesta :

grayloaf24
grayloaf24 grayloaf24
  • 11-08-2020

Answer: I think that this is correct: x^4 - 8x^3 + 7x^2 - 28x + 28

Step-by-step explanation:

Take (x^2-4x)^2 and break it up to solve

(x^2-4x)(x^2-4x)=x^4-8x^3+16x

Then bring in the rest of the equation and add and subtract to solve

x^4-8x^3+16+7x^2-28x+12=x^4-8x^3+7x^2-28x+28

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