anulugwovictor anulugwovictor

11-08-2020
Mathematics

contestada

hi there can you please help me

[tex]t = \sqrt{ \frac{ab - s}{r + ak} } [/tex]

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konrad509 konrad509

11-08-2020

[tex]t=\sqrt{\dfrac{ab-s}{r+ak}}\\\\t^2=\dfrac{ab-s}{r+ak}\\\\rt^2+akt^2=ab-s\\\\akt^2-ab=-rt^2-s\\\\a(kt^2-b)=-(rt^2+s)\\\\a=-\dfrac{rt^2+s}{kt^2-b}\\\\a=-\dfrac{rt^2+s}{-(b-kt^2)}\\\\a=\dfrac{rt^2+s}{b-kt^2}[/tex]

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