Answer:
( y-5) ^2 =-12(x-2)
Step-by-step explanation:
focus at (2,2) and a directrix of x=8
Using the equation
( y-k) ^2 = 4p(x-k)
where ( h,k) is the vertex
The vertex is 1/2 way between the focus and the directrix
( 2+8)/2 , 2
5,2 is the vertex
( y-5) ^2 = 4p(x-2)
distance from the focus to the vertex and from the vertex to the directrix is
|
p|
2-5 = p
-3 = p
( y-5) ^2 = 4*-3(x-2)
( y-5) ^2 =-12(x-2)
