Answer:
The length is [tex]D =3 \ m [/tex]
Explanation:
The velocity of the bullet is mathematically evaluated as
[tex]v = a * t [/tex]
=> [tex]v = 1.5 * 2 [/tex]
=> [tex]v = 3 \ m/s [/tex]
Now from kinematic equation
[tex]v^2 = u^2 + 2* a * D[/tex]
Here D is the length of the barrel and u = 0 m/s
So
[tex]3^2 = 0 + 2* 1.5 * D[/tex]
[tex]D = \frac{9}{3} [/tex]
[tex]D =3 \ m [/tex]
