Answer:
x ≥ - [tex]\frac{3}{13}[/tex]
Step-by-step explanation:
Given
9x + [tex]\frac{2}{3}[/tex](- 7x + 6) - 1 ≥ 2
Multiply through by 3 to clear the fraction
27x + 2(- 7x + 6) - 3 ≥ 6 ← distribute and simplify left side
27x - 14x + 12 - 3 ≥ 6
13x + 9 ≥ 6 ( subtract 9 from both sides )
13x ≥ - 3 ( divide both sides by 13 )
x ≥ - [tex]\frac{3}{13}[/tex]
