Answer:
lim(x---->0) = -5
Step-by-step explanation:
first: sin(x-π/2)= -cosx
so the equation will be :
lim(x---->0) = [-6cos(ax)-1}/cosx
solve :
lim(x---->0) = [-(6cos(a(0))-1}/cos(0)
cos0=1
lim(x---->0)=(-(6(1)-1)/1
lim(x---->0)=-6+1/1
lim(x---->0)=-5
