Answer:
h = 5
Step-by-step explanation:
[tex]16.2=2.7(h+1)\\\\2.7\left(h+1\right)=16.2\\\\\mathrm{Multiply\:both\:sides\:by\:}10\\2.7\left(h+1\right)\cdot \:10=16.2\cdot \:10\\\\Refine\\27\left(h+1\right)=162\\\\\mathrm{Divide\:both\:sides\:by\:}27\\\frac{27\left(h+1\right)}{27}=\frac{162}{27}\\\\Simplify\\h+1=6\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\h+1-1=6-1\\\\Simplify\\h=5[/tex]
