Respuesta :

determine # of solutions using discrimination
D = b^2 - 4 ac
D=8^2 - 4 x 6 x ( -10 )
D = 304
D > 0
The quadratic equation has 2 real solutions
tomson1975

Greetings from Brasil....

Let's solve this 2nd degree equation.

6b² + 8b - 10 = 0       dividing all terms by 2

3b² + 4b - 5 = 0         applying the baskara formula

Δ = 4² - 4 · 3 · (- 5)

Δ = 76

b = (- 4 ± √76)/6      so

b' = (- 4 + √76)/6

b'' = (- 4 - √76)/6

Ver imagen tomson1975