Answer:
386.6 A
Explanation:
We are given;
Solenoid length; L = 10 cm = 0.1 m
Number of turns; N = 247
Magnetic field; B = 1.2 T
Now, at the centre of a long solenoid of N turns/metre carrying a current(I), the formula for the magnetic field is given as;
B = μ_oNI/L
Making I the subject we have;
I = BL/μ_oN
Where μ_o is the vacuum of permeability and has a constant value of 4π × 10^(−7) H/m
Thus;
I = (1.2 × 0.1)/(4π × 10^(−7) × 247)
I = 386.6 A
