Respuesta :
Answer:
\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}
Step-by-step explanation:
\mathrm{Simplify}\:\frac{\left(2ab^3\right)^{-1}}{20\cdot \left(2^{-1}\cdot \:ba^5\right)^2}\cdot \left(\frac{4ab^{-1}}{5b}\right)^{-2}:\quad \frac{5}{32a^{13}b}
