Given:
Graph of positions of Bear A and Bear B.
To find:
The average speed of Bear B in m/min.
Solution:
From the graph it is clear that initial point of graph of Bear B is (0,100) and the end point is (60,2800).
The average speed of Bear B is
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\dfrac{2800-100}{60-0}[/tex]
[tex]m=\dfrac{2700}{60}[/tex]
[tex]m=45[/tex]
Therefore, the average speed of Bear B is 45 m/min.
