nicole5162 nicole5162

01-11-2020
Physics

contestada

A 64.1 kg person is jogging at
2.93 m/s. How much KE does
the jogger have?
(Unit = J)

Respuesta :

01-11-2020

Answer:

275.15 J

Explanation:

Mass of the person = 64.1kg

Speed of person = 2.93m/s

Now,

K.E. = 1/2mv^2

.K.E. = 1/2*64.1*2.93*2.93

K.E. = 275.15 J

Answer Link

Otras preguntas

Please please please please please please please please help with my daily thing

the price of a book is thrice that of an exercise book. of a student spend #9600 on book and #8000 on exercise book, he has 56 items altogether:(a) what is the

Count the possible combinations of 3 letters chosen from A, B, C, D. The possible combinations of 3 letters are __.

Which group suffered the most deaths during the Vietnam War? Vietnamese civilian American soldiers North Vietnamese soldiers South Vietnamese soldiers PLEASE HU

Glenisha checking account had a balance of $973.92. She wrote checks for $91.03 and $13.45. She deposits her paycheck in the amount of 210.90. What is Glenisha'

attachment look at it

What is the interquartile range of the following data set? 2,7,15, 19, 26, 33, 39, 41, 49, 52 A. 26 B. 30 C. 32 D. 22

Convert 77° F into kelvins. Conversion Formulas C° = (F° - 329) - 1.8 Fo= 1.8 x C° + 320 K= C° + 273

Who did Mesopotamians honor in their art and architecture? Why was honoring them so important? Whoever answers correct is getting brainiest btw

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!! DUE TODAY I NEED HELP ASAP A restaurant has a 15% mandatory tip rate. (a) Complete the ratio table shown. Show your work.