Hi there! :)
[tex]\large\boxed{0, 3}[/tex]
3x + 2y = 6
x - y = -3
We can solve the system most easily using substitution. Set the bottom equation equal to x:
x = y - 3
Substitute in this equation for "x" into the top equation:
3(y - 3) + 2y = 6
Distribute the coefficient with terms inside of the parenthesis:
3(y) + 3(-3) + 2y = 6
3y - 9 + 2y = 6
Combine like terms and add 9 to both sides:
5y = 15
y = 3
Substitute in this value of "y" to solve for "x":
x - (3) = -3
x = 0
Therefore, the solution is at (0, 3).
