Answer:
[tex]x=\frac{1-\sqrt{-5} }{6}\\x=\frac{1+\sqrt{-5} }{6}[/tex]
There are no real roots.
Step-by-step explanation:
[tex]6x^2-2x+1=0\\x=\frac{2-\sqrt{2^2-4*6} }{2*6} \\x=\frac{2-\sqrt{-20} }{12}\\x=\frac{1-\sqrt{-5} }{6}\\x=\frac{1+\sqrt{-5} }{6}[/tex]
