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  • 13-11-2020
  • Mathematics
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If sin t = -8/17 and t is a quadrant III angle, find cot t

If sin t 817 and t is a quadrant III angle find cot t class=

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Аноним Аноним
  • 13-11-2020

Answer:cot t = 1.875

[tex]sin t=\frac{-8}{17}[/tex] but sin²t + cos²t = 1 ⇔ cos²t = 1 - sin²t

⇔cos t = [tex]\sqrt{1-sin^{2}t }=\sqrt{1-(\frac{-8}{17})^{2} }=|\frac{15}{17}|[/tex]

but  t is a quadrant III angle => cos t = [tex]\frac{-15}{17}[/tex]

=> cot t = [tex]\frac{-15}{17}:\frac{-8}{17}=\frac{15}{8}=1.875[/tex]

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