timodb3 timodb3

01-12-2020
Mathematics

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Simplify [tex]\sqrt{ \frac{25y^2}{6x}[/tex]
the answer should look smething like this [tex]\frac{b \sqrt{x} }{y}[/tex]

Respuesta :

Hrishii Hrishii

01-12-2020

Answer:

[tex] \frac{5y \sqrt{6x} }{6x} [/tex]

Step-by-step explanation:

[tex]\sqrt{ \frac{25y^2}{6x}} \\ \\ = \frac{5y}{ \sqrt{6x} } \\ \\ = \frac{5y \sqrt{6x} }{ \sqrt{6x} \times \sqrt{6x} } \\ \\ = \frac{5y \sqrt{6x} }{6x} [/tex]

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