sandith6al2es
sandith6al2es sandith6al2es
  • 15-10-2016
  • Mathematics
contestada

\(f(27)=\) \(\sqrt{2x-5}\)

Respuesta :

monbon
monbon monbon
  • 15-10-2016
How to solve:

1. Take f, which is 27, and plug that in for x. 

[tex]\(f(27)=\) \(\sqrt{2x-5}\)[/tex]
[tex]\(f(27)=\) \(\sqrt{2(27)-5}\)[/tex]

2. multiply 27 by 2. 
2 x 27 = 54
[tex](f(27)=\) \(\sqrt{54-5}\)[/tex]

3. Subtract 5 from 54.
54 - 5 = 49
[tex](f(27)=\) \(\sqrt{49}\)[/tex]

4. square root 49. 

[tex](f(27)=\) \(7}\)[/tex]


The answer is 7. 

Answer Link

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