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  • 11-12-2020
  • Physics
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A spring with a constant of 92N/m is compressed 2.8 cm. How much potential energy is stored in the spring?

PE= J

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quasarJose
quasarJose quasarJose
  • 12-12-2020

Answer:

0.036J

Explanation:

Given parameters:

Spring constant , K  = 92N/m

Compression  = 2.8cm  = 0.028m

Unknown:

Potential energy  = ?

Solution:

To solve this problem;

          P.E  =[tex]\frac{1}{2}[/tex] K e²

 K is the spring constant

 e is the compression

so;

      P.E = [tex]\frac{1}{2}[/tex]  x 92 x 0.028²  = 0.036J

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