Answer:
[tex]x \le -4[/tex]
Step-by-step explanation:
Given
[tex]\qquad16x - 7 \leq -71[/tex]
Required
Solve
Start by adding 7 to both sides
[tex]\qquad16x - 7 + 7 \leq -71 + 7[/tex]
[tex]\qquad16x - 7 + 7 \leq -64[/tex]
[tex]\qquad16x \leq -64[/tex]
Divide both sides by 16
[tex]\frac{16x}{16} \leq \frac{-64}{16}[/tex]
[tex]\frac{16x}{16} \leq -\frac{64}{16}[/tex]
[tex]x \leq -\frac{64}{16}[/tex]
[tex]x \le -4[/tex] --- The solution
