Answer:
[tex] \sqrt{2x - 5} + 4 = x \\ \sqrt{2x - 5} = x - 4 \\ 2x - 5 = {(x - 4)}^{2} \\ 2x - 5 = {x}^{2} - 8x + 16 \\ {x}^{2} - 10x + 21 = 0 \\ {x}^{2} - 3x - 7x + 21 = 0 \\ x(x - 3) - 7(x - 3) = 0 \\ (x - 3)(x - 7) = 0 \\ \boxed{x = 3 \: or \: x = 7}[/tex]
x=3 or x=7 is the right answer.
