abigailbarnes8242 abigailbarnes8242
  • 04-02-2021
  • Mathematics
contestada

Solve the equation for x:
sin^2 x – 2 cos x - 2 = 0
for the restriction 0 < x < 2pi

Solve the equation for x sin2 x 2 cos x 2 0 for the restriction 0 lt x lt 2pi class=

Respuesta :

Аноним Аноним
  • 04-02-2021

Answer: x = pi

sin²x - 2cos x - 2 = 0

⇔ 1 - cos²x - 2cos x - 2 = 0

⇔ cos²x + 2cos x + 1 = 0

⇔ (cos x + 1)² = 0

⇒ cos x + 1 = 0

⇔ cos x = -1

⇒ x = pi + k2pi

because 0 ≤ x < 2pi

=> x = pi

Step-by-step explanation:

Answer Link

Otras preguntas

HOW TO FIND THE MISSING NUMERATOR IN ANY FRACTIONS LIKE 4/8=  ?/4
How do you say I was born in the Philippines in Spanish
My daughter needs a synonym for tired and all the word she has is problem , story and banquet
how does.debate in the senate differ from debate in the house?
Explain why the railroads were not built in a straight line from east to west.
Can someone help me in probability?Amanda wrote a computer program that generates two random numbers between one and eleven.When she runs it,what is the probabi
how could you compare the energy carried in two different longitudinal waves
Why did populations soar between 1800 and 1900?
There is a turtle race. The race will last 2 minutes. I have to find the distance from the start each turtle will be at the end of the race. Speed (in inches pe
Write an equation for a non-vertical line that contains the point ( 2,-4 )