Answer:
x<23
Step-by-step explanation:
Find the diagram attached
Perimeter of the rectangle = 2(L+W)
L is the length
W is the width
Given
L = x
W = x+4
If the perimeter of the rectangle is less than 100, then;
P < 100
2(x+x+4)<100
2(2x+4)<100
4x+8<100
4x<100-8
4x<92
x<92/4
x<23
Hence the required solution is x<23
