Answer: [tex]r \ge -\frac{49}{11}[/tex]
r is greater than or equal to the fraction -49/11
==========================================================
Work Shown:
[tex]r + 5(-2r-10) \le -4r - 1 + 6r\\\\r - 10r - 50 \le -4r - 1 + 6r\\\\-9r - 50 \le 2r - 1\\\\-9r-2r \le - 1 + 50\\\\-11r \le 49\\\\r \ge \frac{49}{-11}\\\\r \ge -\frac{49}{11}\\\\[/tex]
Note how the inequality sign flips. This happens any time you divide both sides by a negative number.
