MimiClumZy
MimiClumZy MimiClumZy
  • 11-03-2021
  • Mathematics
contestada

• PQ²+PR²=QR²
• PQ²+QR²=PR²
• PR²- PQ²=QR²
• PR²- QR²=PQ²
​

PQPRQR PQQRPR PR PQQR PR QRPQ class=

Respuesta :

tanmayakumarp3
tanmayakumarp3 tanmayakumarp3
  • 11-03-2021

Answer:

Option A

[tex] {pq}^{2} + {pr}^{2} = {qr}^{2} [/tex]

Step-by-step explanation:

This is because here,

PQ is the Height of the right triangle.

QR is the Base of the right triangle.

PR is the Hypotenuse of the right triangle.

So, as according to Pythagoras Theorem,

[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]

Also,

[tex] {pq}^{2} + {qr}^{2} = {pr}^{2} [/tex]

Not,

[tex]{pq}^{2} + {pr}^{2} = {qr}^{2} [/tex]

Hence, Option A is not correct.

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