Answer:
h(0)=10
h(4)=16
Step-by-step explanation:
for h(0) you would need to do the second equation because it is within the bounds of the variable.
h(0)= 2x^2 - 3x + 10
anything times 0 is 0
so 2(0)^2 - 3(0) + 10=
0-0+10=
10
h(4) would use the third equation since it's the only one that agrees with the variable 4
2^4=16
