Answer:
9.11
Step-by-step explanation:
Given that,
[tex]\dfrac{x}{y}=-3[/tex]
We need to find the value of [tex]\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}[/tex]
The value of [tex]\dfrac{y}{x}=\dfrac{-1}{3}[/tex]
So,
[tex]\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}=(\dfrac{x}{y})^2+(\dfrac{y}{x})^2\\\\=(-3)^2+(\dfrac{-1}{3})^2\\\\=9+\dfrac{1}{9}\\\\=9.11[/tex]
So, the required answer is equal to 9.11.
