Answer:
0.423M
Explanation:
The reaction of acetic acid with NaOH is:
CH₃CO₂H + NaOH → CH₃CO₂Na + H₂O
That means the moles of NaOH added = Moles acetic acid in the solution
To solve this problem we need to find the moles of NaOH added to find the moles of acetic acid and its concentration using its volume as follows:
Moles NaOH:
29.6mL = 0.0296L * (0.250mol / L)= 0.0074 moles NaOH = Moles acetic acid
Molarity acetic acid:
0.0074 moles / 0.0175L =
0.423M
