Answer:
0.559 L
Explanation:
Step 1: Given data
Moles of sodium iodide (n): 0.405 mol
Molar concentration of sodium iodide (M): 0.724 M (0.724 mol/L)
Step 2: Calculate the volume of solution (V)
The molarity is equal to the moles of solute divided by the liters of solution.
M = n/V
V = n/M
V = 0.405 mol/(0.724 mol/L) = 0.559 L
(hope this helps can i plz have brainlist :D hehe)
