elanenahunter elanenahunter
  • 12-04-2021
  • Chemistry
contestada

Calculate the number of moles in 7.04 g of lead (II) nitrate, Pb(NO3)2
Can Someone help me covert this?!

Respuesta :

drpelezo
drpelezo drpelezo
  • 12-04-2021

Answer:

moles Pb(NO₃)₂ ≅ 0.0213 mole (three sig. figs.)

Explanation:

converting...

grams to moles => divide by formula weight

moles to grams => multiply by formula weight

for this problem ...

moles Pb(NO₃)₂ = 7.04g / 331.2g/mol = 0.021256 (calculator answer)

≅ 0.0213 mole (three sig. figs.)

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