Myselfll
Myselfll Myselfll
  • 12-04-2021
  • Mathematics
contestada

what is the range. f(x)=x^2+6x+8​

Respuesta :

chrissgen2005
chrissgen2005 chrissgen2005
  • 12-04-2021

Answer:

The range is [-11, ∞).

Step-by-step explanation:

f(x)=3x^2+6x-8

This is a parabola which opens upwards.

Convert to vertex form:

= 3(x^2 + 2x) - 8

= 3 [ (x + 1)^2 - 1] - 8

= 3(x + 1)^2 - 3 - 8

=  3(x + 1)^2 - 11.

The minimum value is -11 so the range is [-11, ∞).

Step-by-step explanation:

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