Answer:
y-int.=6; vertex equation: y= (x - 2)² + 10; vertex: (2, 10); axis of symmetry: x = 2
Step-by-step explanation:
The c value can be used as the y-int.: y=6
vertex form: a(x-h)²+ k
vertex form of this equation:
use completing the square method
y=x²+4x+6
take b, it, divide it in half, then square it (b/2)². b/2 is your h value. Add (b/2)² to c to get your k value
y= x²+4x + 2² + 6
y= (x - 2)² + 4 + 6
vertex equation:
y= (x - 2)² + 10
vertex: (2, 10)
axis of symmetry:
use the h value: x = 2
