Given:
The length of the rectangle = [tex]y^2+3y+7[/tex]
Width of the rectangle = [tex]y-3[/tex]
To find:
How much longer is the length?
Solution:
We need to find the difference between length and width of the rectangle.
[tex]Difference=Length-Width[/tex]
[tex]Difference=y^2+3y+7-(y-3)[/tex]
[tex]Difference=y^2+3y+7-y+3[/tex]
[tex]Difference=y^2+(3y-y)+(7+3)[/tex]
[tex]Difference=y^2+2y+10[/tex]
Therefore, the length of the rectangle is [tex]y^2+2y+10[/tex] much longer than the width.
