Respuesta :

theleangreenbean

Answer:

x=32, x=0

Step-by-step explanation:

[tex](x-16)^2=256[/tex]

Take the square root of both sides

[tex]\sqrt{ (x-16)^2}=\±\sqrt{256}\\x-16=\±16[/tex]

x=16+16 or x=16-16

Therefore, x=32 or x=0

I hope this helps!

marisacireddu

Answer:

x=32 and x=0

Step-by-step explanation:

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