Answer:
(n-2)²
Step-by-step explanation:
If triangle PQR is similar to triangle XYZ, then;
PQ/QR =XY/YZ
Given
PQ = n + 2,
QR = n - 2 and
XY=n^2 - 4,
Substitute
n+2/n-2 = n²-4/YZ
n+2/n-2 = (n+2)(n-2)/YZ
1/n-2 = n-2/YZ
Cross multiply
YZ = (n-2)(n-2)
YZ = (n-2)²
Hence the value of YZ in terms of n is (n-2)²
