taniawashington
taniawashington taniawashington
  • 15-04-2021
  • Mathematics
contestada

Answer this please...........

Answer this please class=

Respuesta :

mimifarooqui13
mimifarooqui13 mimifarooqui13
  • 15-04-2021

okay lets begin with the first part of it which is tan

sinx=p/h -----> some people have  

cosx=b/h ----> curly brown hair  

tanx=p/b -----> through proper brushing

an easy way to remember the ratios ^

we have sin and cos so we can say that the h=41 b= 40 and p is 9

so tan will be [tex]tanA=\frac{9}{40}[/tex]

now csc sec and cot are reciprocals of sin cos and tan

so sinA is 9/41 cscA will be 41/9

cosA is 40/41 secA will be 41/40

tanA is 40/9 cotA will be 40/0

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