Answer:
ΔT = 0.29°C
Explanation:
Using the law of conservation of energy:
[tex]Potential\ Energy = Thermal\ Energy\\mgh = mC\Delta T\\gh = C\ \Delta T\\\\\Delta T = \frac{gh}{C}[/tex]
where,
ΔT = Temperature difference between the water at the top and the bottom of the fall = ?
g = acceleration due to gravity = 9.81 m/s²
h = height of fall = 125 m
C = specific heat capacity of water = 4200 J/kg
Therefore,
[tex]\Delta T = \frac{(9.81\ m/s^2)(125\ m)}{4200\ J/kg^oC}\\\\[/tex]
ΔT = 0.29°C
