creid84 creid84
  • 14-05-2021
  • Mathematics
contestada

[tex]24x^{2}+bx^{2} =25x^{2}[/tex]

Respuesta :

s20109293775
s20109293775 s20109293775
  • 15-07-2021

Answer:

x = 0

Step-by-step explanation:

Subtract 25x^2 from both sides

24x^2 + bx^2 - 25x^2 - 25x^2

Simplify

bx^2 - x^2 = 0

Factor bx^2 - x^2: x^2(b - 1)

bx^2 - x^2

Factor out common term x^2

= x^2 (b - 1)

x^2(b - 1) = 0

Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0

x^2 = 0

Apply rule x^n = 0   x = 0

x = 0

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