Answer:
f'(2) = 1/4
Step-by-step explanation:
We know that:
g(x) = x^3 + x
and f(x) is the inverse function of g(x), such that:
f(2) = 1
this is because:
g(1) = 1^3 + 1 = 2
We want to find:
f'(2)
The general formula for this case is:
if f(x) is the inverse of g(x)
and f(x) = y
then:
f'(y) = 1/g'(x)
Then in this case,
f'(2) = 1/g'(1)
so we just need to differentiate g(x)
g'(x) = 3*x + 1
and:
g'(1) = 3*1 + 1 = 4
Then:
f'(2) = 1/g'(1) = 1/4
f'(2) = 1/4
