tracytrinh000 tracytrinh000
  • 15-06-2021
  • Mathematics
contestada

solve the following quadratic equation 1(x+3)^2-1=0

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 15-06-2021

Answer:

x=-2, -4

Step-by-step explanation:

1(x+3)^2-1=0

Add 1 to each side

1(x+3)^2-1+1=0+1

(x+3)^2=1

Take the square root of each side

sqrt((x+3)^2)=sqrt(1)

x+3 = ±1

x+3 = 1    x+3 = -1

Subtract 3 from each side

x+3-3 = 1-3    x+3-3 = -1-3

x = -2     x=-4

Answer Link
HelpfulChaos HelpfulChaos
  • 15-06-2021

Answer:

X = -2 X = -4

Step-by-step explanation:

Ver imagen HelpfulChaos
Answer Link

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