Answer:
sin x
Step-by-step explanation:
sin ^2 x + sin x + cos ^ x -1
sin ^2 x + cos ^ x + sin x-1
We know that sin^2 x + cos ^2 x = 1
1 + sin x -1
Hi!
[tex]\sin^2x+\sin x+\cos^2 x-1=\\\\=\underline{\sin^2x+\cos^2x}+\sin x-1=\\\\=1+\sin x-1=\boxed{\sin x}[/tex]
