Explanation: BC and BD are congruent. I forgot the name of the theorem but it involves proving the bisected angle’s triangles congruent. So here’s my attempt at that: Angle: Angle BAC and BAD are congruent as they are bisected. Angle: The right angles are congruent. Side: BA is congruent for both triangles. The triangles are congruent by AAS, so BC and BD must be congruent. BC=BD x-1=3x-11 10=2x x=5