5y49r7md8g 5y49r7md8g
  • 13-07-2021
  • Physics
contestada

What bet force is required to stop a 2250 kg car if the decelerates at a rate of -4.3 m/s^2 please answer fast

Respuesta :

Аноним Аноним
  • 13-07-2021

Answer:

Force = Mass × Acceleration

[tex]{ \tt{force = 2250 \times 4.3}} \\ = { \tt{9675 \: newtons}}[/tex]

Answer Link

Otras preguntas

How do I solve n^2-5n-14=0 by factoring
What is the sum of the first 4 terms of the arithmetic sequence in which the 6th term is 8 and the 10th term is 13 ? F. 10.5 G. 14.5 H. 18 J. 21.25 K. 39.5
solve the equation 4x^2-17x-15=0
what is the function of hyperbole in poetry?
Which of the following is equivalent to (5 /k) + ((k + 3) /(k + 5)) ? A. (k +8) /(2k + 5) B. (k + 8) /k(k + 5) C. 5(k + 3) /k(k + 5) E. (k^2+ 8k + 25) /k(k + 5)
what is a tragic protagonist?
I need help to graphs these problem please
I don't understand how to get 50000 ohms, please can someone help? I would have just left my answer at 25,000 ohms!
(x^3)^9 = A: x^12 B: x^27 C: x^3 D: x^6
The expression −8x^3(7x^6 − 3x^5) is equivalent to: A. −56x^9 + 24x^8 B. −56x^9 − 24x^8 C. −56x^18 + 24x^15 D. −56x^18 − 24x^15 E. −32x^4