hmartinezmelendez22 hmartinezmelendez22
  • 14-07-2021
  • Mathematics
contestada

y = -4(x + 6)(x - 8)
How do you write this in standard form?

Respuesta :

theleangreenbean
theleangreenbean theleangreenbean
  • 14-07-2021

Answer:

[tex]y = -4x^2 + 8x + 192[/tex]

Step-by-step explanation:

Hi there!

Standard form: [tex]y=ax^2+bx+c[/tex]

[tex]y = -4(x + 6)(x - 8)[/tex]

Use the distributive property to multiply (x+6) and (x-8)

[tex]y = -4(x(x - 8) + 6(x - 8))\\y = -4(x^2 - 8x + 6x - 48)\\y = -4(x^2 - 2x - 48)[/tex]

Multiply the parentheses by -4

[tex]y = -4x^2 + 8x + 192[/tex]

I hope this helps!

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